Program 23) A class of n students take an annual examination in m subjects. Given program read the marks obtained by each students in various subjects and to compute and print the total marks obtained by each of them.
The program uses two for loops, one for controlling the number of students and the other for controlling the number of subjects. Since both the number of students and the number of subjects are requested by the program, the program may be used for a class of any size and any number of subjects.
The outer loop includes three parts:
(1) reading of roll numbers of students, one
after another;
(2) inner loop, where the marks are read and
totalled for each student; and
(3) printing of total marks and declaration
of grades.
PROGRAM
#define FIRST 360
#define SECOND 240
main ( )
{
int n, m, i, j, roll_numbers, marks, total ;
printf ("Enter number of students and subjects\n") ;
scanf ("%d %d", &n, &m) ;
for (i = 1; i <= n; ++i)
{
printf ("Enter roll_number : ") ;
scanf (%d', &roll_number) ;
total = 0 ;
printf ("\nEnter marks of %d subjects for ROLL
NO %d\n", m, roll_number) ;
for (j =1; j <= m; j++)
{
scanf ("%d", &marks) ;
total = total + marks ;
}
printf ("TOTAL MARKS = %d", total) ;
if (total >= FIRST)
printf (" (FIRST DIVISON)\n\n") ;
else if (total <= SECOND)
printf (" (second Divison)\n\n") ;
else
printf (" (***FAIL*** )\n\n") ;
}
}
Output: Enter number of students and subjects
3 6
Enter roll number : 8701
Enter marks of 6 subjects for ROLL NO 8701
81 75 83 45 61 59
TOTAL MARKS = 404 ( FIRST DIVISON )
Enter roll_number : 8702
Enter marks of 6 subjects for ROLL NO 8702
51 49 55 47 65 41
TOTAL MARKS = 308 ( Second Divison )
Enter roll number : 8704
Enter marks of 6 subjects for ROLL NO 8704
40 19 31 47 39 25
TOTAL MARKS = 201 ( ***FAIL*** )
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